@CalAldred

Baseball Data Scientist. Opinions my own.

 Wrigleyville
github.com/caldred/PitchSim
Joined June 2013
  • Tweets516
  • Following670
  • Followers516
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OpenAI made a huge mistake not renaming GPT-6 Sol to GPT-6 Terra once it became clear it was mogged by Opus 5.5 You had a whole tier sitting there to bail you out! Use it!
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I’d like to ban everyone on Twitter from ever discussing the “max” reasoning mode ever again. The only reason it exists is to inflate benchmarks by pushing models to solve overly complex tasks in one shot that no reasonable person would ever ask a model to do all at once
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If it takes max reasoning the model can’t actually do it in one shot, just wait for the next gen
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Why are the Barenaked Ladies singing in 4 different keys??
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Replying to @BEBischof @CalAldred
I literally generated the first hundred or so, if anyone is curious. This is for both even and odd fiber degree: jacobianfun.org/counterexamp…
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Coming soon from the machine gods: the infinite ladder is just one row of a two-parameter factory of Jacobian counterexamples. The original map sits at (1,1), and every mapping degree from 3 onward appears.
Cal Aldred@CalAldredJul 20
Came up with a way to generate an infinite family of counterexamples, via Fable + GPT 5.6 Sol
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Came up with a way to generate an infinite family of counterexamples, via Fable + GPT 5.6 Sol
levent
@__alpoge__Jul 20
hello there the jacobian conjecture is false thanx to my close friend akhil for asking about it and my other close friend fable for working during the world cup final ((1+xy)^3 z + y^2 (1+xy) (4+3xy), y + 3 x (1+xy)^2 z + 3 x y^2 (4+3xy), 2 x - 3 x^2 y - x^3 z): \C^3\to \C^3, has jacobian determinant -2, and sends (0, 0, -1/4), (1, -3/2, 13/2), and (-1, 3/2, 13/2) to (-1/4, 0, 0)
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xitter.cf/CalAldred/status/20793…
Cal Aldred@CalAldredJul 21
There's an infinite ladder of this geometric construction too, per GPT 5.6 Sol and Fable 5! Integrate D^{m−1} for a quadratic D, mark a root of the primitive, forget the mark. Generically 2m−1 sheets, so no two rungs are polynomially equivalent.
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There's an infinite ladder of this geometric construction too, per GPT 5.6 Sol and Fable 5! Integrate D^{m−1} for a quadratic D, mark a root of the primitive, forget the mark. Generically 2m−1 sheets, so no two rungs are polynomially equivalent.
Andy Jiang@davikrehaltJul 20
Replying to @littmath @__alpoge__
GPT: Take π: P¹ × Sym²(P¹) → Sym³(P¹), (p, {q,r}) ↦ {p,q,r}. R be its ramification divisor; H ⊂ Sym³(P¹) ≅ P³ be hyperplane tangent but not osculating to the small diagonal; X := (P¹ × Sym²(P¹)) \ (R ∪ π⁻¹(H)) ≅ A³; Y := Sym³(P¹) \ H ≅ A³. π|X: X → Y is counterexample
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Someone needs to make a benchmark for the benchmarks that benchmarks how hard it is for an AI agent to tell that the benchmark is in fact a benchmark
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Our team is hiring a machine learning engineer. Come work with me and the rest of our baseball analytics team on building models touching all areas of Cubs baseball: my1060wd.wd5.myworkdayjobs.c…
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Urbanism fun fact of the day: 11 of the 15 most densely populated urban areas in the US with over 300k population are in California
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Excited to announce that I’ve joined the @Cubs front office as an Analyst, Baseball Analytics! It’s a great group, can’t wait to get working towards the @Cubs next championship
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Oregon most definitely has that dawg in em
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Not enough dawg apparently
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Everyone say hi to Pupusa
Why you should have a cat
@ShouldHaveCat9 Oct 2023
His name is the last thing you ate
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[Ryan Noda Intensifies]
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Cal Aldred retweeted
Cal Aldred@CalAldred1 Sep 2023
I’m a little late to the party but: GC Kuss! GC Kuss! GC Kuss! 🦅🇺🇸🦅🇺🇸🦅🇺🇸🦅🇺🇸🦅🇺🇸🦅🇺🇸🦅🇺🇸 @LanterneRougeCP
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