Replying to @JadeMasterMath @mattecapu
Wondering how that's even symmetric? (is it?) I suppose by taking some left or right adjoints you can turn L \tens M into M \tens L?
Replying to @TonyTheLion2500
They don't tell you this but presheaves are better than sheaves even though they have the derogatory name
Replying to @no_earthquake
Live from New York it's Saturday Night!
Replying to @Glorbutron @davidad
Oh fair enough. Is that true in some pathological Hilbert spaces?
Replying to @davidad
Do you have some exotic space in mind where orthogonal doesn't imply linear independent? I think in a vector space it should be true right?
Category Witch retweeted
I can suggest an equation that has the potential to impact the future:
𝐍𝐚𝐭(𝐇𝐨𝐦(−, 𝐶), 𝐹) ≅ 𝐹(𝐶) + AI
Given a category 𝒞, a functor 𝐹 : 𝒞ᵒᵖ → 𝐒𝐞𝐭, and an object 𝐶 ∈ 𝒞.
This equation combines Yoneda’s famous Yoneda lemma, which relates a category (𝒞) to a functor (𝐹: 𝒞ᵒᵖ → 𝐒𝐞𝐭) and the speed of light (𝐶 ∈ 𝒞), with the addition of Al (Artificial Intelligence). By including Al in the equation, it symbolizes the increasing role of artificial intelligence in shaping and transforming our future. This equation highlights the potential for Al to unlock new forms of energy, enhance scientific discoveries, and revolutionize various fields such as healthcare, transportation, and technology.
Replying to @garvvee
I don't know if computers just take binary input, at least that's a pretty reductionist way of looking at it. How would this capture running two programs at once for example.
By the way, the set in question is infinite sequences not finite ones.
I think this is more like a particular choice of semantics for programs, which makes sense in some contexts but not others. Or maybe I'm missing the point that all programs can be reduced to these somehow?
Replying to @BarbaraFantechi
You MUST include the points at infinity
Replying to @fabgenovese
If the product is free then you are the product!
The reason for this is because a lax functor 1 -> D is the same as a monad in D, so making it normal means there's no algebras and you have to add them back in to get an equivalence
Replying to @myers_jaz @BowToChris
Well you've got an equivalence
normal lax C -> Alg(D)
And
lax C -> D
So Alg is actually the right adjoint. I think that makes normal lax functors a coreflective subcategory?
Replying to @BarbaraFantechi @themathgay
👀 what is it an Euler characteristic of?
Replying to @BowToChris
Well there's the thing where you invert spans to get profunctors but that only gets discrete categories so not quite










